How Many Triangles?
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- Alexandre Orion
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- om mani padme hum
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(I could have never been admitted to the Academy.) :blush:
(( I'm also impatient to show people just what a twit I really am ... ))
:huh:
((( ... and I think I counted some twice ... )))
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But I may have missed some...
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- RyuJin
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Edit: I'm highly tempted to cut one out and start moving pieces now that my mind is so enthralled with the challenge... :whistle:
Through passion I gain strength and knowledge
Through strength and knowledge I gain victory
Through victory I gain peace and harmony
Through peace and harmony my chains are broken
There is no death, there is the force and it shall free me
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Out of darkness, he brings light. Out of hatred, love. Out of dishonor, honor-james allen-
He who has conquered doubt and fear has conquered failure-james allen-
The sword is the key to heaven and hell-Mahomet-
The best won victory is that obtained without shedding blood-Count Katsu-
All men's souls are immortal, only the souls of the righteous are immortal and divine -Socrates-
I'm the best at what I do, what I do ain't pretty-wolverine
J.L.Lawson,Master Knight, M.div, Eastern Studies S.I.G. Advisor (Formerly Known as the Buddhist Rite)
Former Masters: GM Kana Seiko Haruki , Br.John
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Former Apprentices:Adhara(knight), Zenchi (knight)
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- Alexandre Orion
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MCSH wrote: 56... and can prove it:D
THAT'S OUR SAJJAD !!!!!
... now, please show us.
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- RyuJin
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Now I'm not just using the obvious easy to spot triangles but also the triangles over triangles...wish I had the right software to show what I mean...
Through passion I gain strength and knowledge
Through strength and knowledge I gain victory
Through victory I gain peace and harmony
Through peace and harmony my chains are broken
There is no death, there is the force and it shall free me
Quotes:
Out of darkness, he brings light. Out of hatred, love. Out of dishonor, honor-james allen-
He who has conquered doubt and fear has conquered failure-james allen-
The sword is the key to heaven and hell-Mahomet-
The best won victory is that obtained without shedding blood-Count Katsu-
All men's souls are immortal, only the souls of the righteous are immortal and divine -Socrates-
I'm the best at what I do, what I do ain't pretty-wolverine
J.L.Lawson,Master Knight, M.div, Eastern Studies S.I.G. Advisor (Formerly Known as the Buddhist Rite)
Former Masters: GM Kana Seiko Haruki , Br.John
Current Apprentices: Baru
Former Apprentices:Adhara(knight), Zenchi (knight)
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Alexandre Orion wrote:
MCSH wrote: 56... and can prove it:D
THAT'S OUR SAJJAD !!!!!
... now, please show us.
Count those that have the bottom edge and the 2 other edges are equal (4)
Now we'll count those on left side and then multiply it by 2, (to cover those on right as well)
To count those on left, you can count those that their right edge is lowest line that comes from right, and then multiply it by 4.
They are:
3 small ones + 2 made of two small triangle + 1 made of 3 triangles + 3 that have bottom line (9)
Weird... it results in 76... I should've made a mistake in calculation last time
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Adhara wrote: I got 8 or 80, depending on what you count as a triangle
But I may have missed some...
Nope, I'm at 80 now too
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- Alexandre Orion
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-- Crop the photo ;
-- Photoshop it to colour in the triangle ;
-- Then there's one.
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MCSH wrote:
Alexandre Orion wrote:
MCSH wrote: 56... and can prove it:D
THAT'S OUR SAJJAD !!!!!
... now, please show us.
Count those that have the bottom edge and the 2 other edges are equal (4)
Now we'll count those on left side and then multiply it by 2, (to cover those on right as well)
To count those on left, you can count those that their right edge is lowest line that comes from right, and then multiply it by 4.
They are:
3 small ones + 2 made of two small triangle + 1 made of 3 triangles + 3 that have bottom line (9)
Weird... it results in 76... I should've made a mistake in calculation last time![]()
My solution:
Taking the line from bottomright to bottomleft, the lowest line on the left goes across to meet the line bottomright<->top. Using the lines that leave the bottomright point you can make 4 triangles that use that point.
Taking the point that intersects the lowest line from bottomright with the lowest line bottomleft, you can use the other lines bottomright<->top to make 3 triangles that use that point. (remembering that it is one less because there is one fewer line (the bottom one) being used)
Follow this for the other two points that intersect with the lowest line from bottomleft and you can make 2 triangles and then 1 triangle.
4+3+2+1=10
That can be done with each of the (4) lines leaving bottomleft point so you have 4x10=40 and that can be doubled by mirroring it on the other side so 2x40=80
At least I think that's right
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Akkarin wrote:
MCSH wrote:
Alexandre Orion wrote:
MCSH wrote: 56... and can prove it:D
THAT'S OUR SAJJAD !!!!!
... now, please show us.
Count those that have the bottom edge and the 2 other edges are equal (4)
Now we'll count those on left side and then multiply it by 2, (to cover those on right as well)
To count those on left, you can count those that their right edge is lowest line that comes from right, and then multiply it by 4.
They are:
3 small ones + 2 made of two small triangle + 1 made of 3 triangles + 3 that have bottom line (9)
Weird... it results in 76... I should've made a mistake in calculation last time![]()
My solution:
Warning: Spoiler!Only focusing on one side for a second:
Taking the line from bottomright to bottomleft, the lowest line on the left goes across to meet the line bottomright<->top. Using the lines that leave the bottomright point you can make 4 triangles that use that point.
Taking the point that intersects the lowest line from bottomright with the lowest line bottomleft, you can use the other lines bottomright<->top to make 3 triangles that use that point. (remembering that it is one less because there is one fewer line (the bottom one) being used)
Follow this for the other two points that intersect with the lowest line from bottomleft and you can make 2 triangles and then 1 triangle.
4+3+2+1=10
That can be done with each of the (4) lines leaving bottomleft point so you have 4x10=40 and that can be doubled by mirroring it on the other side so 2x40=80
At least I think that's right
You are counting those at center twice
Master: Wescli Wardest
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